Saved Bookmarks
| 1. |
Check that the ratio (ke^(2))/(Gm_(e)m_(p))is dimensionless. Look up a table of physical constants and determine the value of this ratio. What does the ratio signify ? |
|
Answer» Solution :Given ratio is `(ke^(2))/(Gm_(e)m_(p))`………(1) Now, above ratio is EQUIVALENT to, `((ke^(2))/(r^(2)))/((Gm_(e)m_(p))/r^(2)) =- F_(e)/F_(g)` Obviously above ratio is UNITLESS and HENCE dimensionless because it is a ratio of TWO IDENTICAL physical quantities. |
|