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Check whether the following matrices are in vertible or not :\( \begin{bmatrix}1 & 0 \\[0.3em]0 & 1 \\[0.3em]\end{bmatrix}\)[1,0,0,1] |
Answer» Given, [1,0,0,1] Let A =\( \begin{bmatrix}1 & 0 \\[0.3em]0 & 1 \\[0.3em]\end{bmatrix}\) Then, |A| = \( \begin{vmatrix}1 & 0 \\[0.3em]0 & 1 \\[0.3em]\end{vmatrix}\) = 1 – 0 = 1 ≠ 0. ∴ A is a non-singular matrix. Hence, A-1 exists. |
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