Choose two consecutive numbers whose product exceeds the square of the

1.	Choose two consecutive numbers whose product exceeds the square of the smaller number by 9
Answer» Answer: 9,10 Step-by-step EXPLANATION: let X and x+1 be the 2 consecutive no.s given that, x(x+1) = x²+9 => x²+x = x²+9 => x = 9 so, the 2 no.s are 9,9+1 ie, 9 and 10 Verification product of 9 and 10 = 910 = 90 ----------- (1) SQUARE of the SMALLER no. = 99 = 81 => product = sqr(smaller NUMBER) + 9 hence verified

Choose two consecutive numbers whose product exceeds the square of the smaller number by 9

Answer»

Answer:

9,10

Step-by-step EXPLANATION:

let X and x+1 be the 2 consecutive no.s

given that, x(x+1) = x²+9

=> x²+x = x²+9

=> x = 9

so, the 2 no.s are 9,9+1

ie, 9 and 10

Verification

product of 9 and 10 = 9*10 = 90 ----------- (1)

SQUARE of the SMALLER no. = 9*9 = 81

=> product = sqr(smaller NUMBER) + 9

hence verified