1.

CIhr: H+ JTS find the value of a the

Answer»

a^3 + b^3= (a+b)^3 - 3ab (a +b)

(4 +root 15 +4 - root 15 )^3 -3 ×(4+roor15) × (4-root15)(4+root15 +4- rot15)

here 1/4 +root 15= 4-root 15

here (a+b)(a-b)=a^2-b^2

8^3 - 3(16-15) ×8

=512-24

=488

488 is the answer of the following


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