InterviewSolution
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InterviewSolution
| 1. |
CIhr: H+ JTS find the value of a the |
| Answer» <p>a^3 + b^3= (a+b)^3 - 3ab (a +b)</p><p>(4 +root 15 +4 - root 15 )^3 -3 ×(4+roor15) × (4-root15)(4+root15 +4- rot15)</p><p>here 1/4 +root 15= 4-root 15</p><p>here (a+b)(a-b)=a^2-b^2</p><p>8^3 - 3(16-15) ×8</p><p>=512-24</p><p>=488</p> <p>488 is the answer of the following</p> | |