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Class 10th solve fast |
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Answer» AREA of TRIANGLE = (1/2)xbasexheight Area (ΔABC) = (1/2)X BCxAB Area (ΔADC) = (1/2)x ADxAB Therefore, Area (ΔABC) BC ——————- = —- = 4/8 = 1/2 Area (ΔADC) AD |
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