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Class 10th solve fast​

Answer» AREA of TRIANGLE = (1/2)xbasexheight

Area (ΔABC) = (1/2)X BCxAB
Area (ΔADC) = (1/2)x ADxAB

Therefore,
Area (ΔABC) BC
——————- = —- = 4/8 = 1/2
Area (ΔADC) AD


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