Classify the angle whose magnitudes are given below

1.	Classify the angle whose magnitudes are given below
Answer» ANSWER: This implies that x2+2ax=4x−4a−13 or x2+2ax−4x+4a+13=0 or x2+(2a−4)x+(4a+13)=0 Since the equation has just ONE solution INSTEAD of the usual two distinct SOLUTIONS, then the two solutions must be same i.e. discriminant = 0. Hence we get that (2a−4)2=4⋅1⋅(4a+13) or 4a2−16a+16=16a+52 or 4a2−32a−36=0 or a2−8a−9=0 or (a−9)(a+1)=0 So the values of a are −1 and 9.

Answer»

This implies that

x2+2ax=4x−4a−13

x2+2ax−4x+4a+13=0

x2+(2a−4)x+(4a+13)=0

Since the equation has just ONE solution INSTEAD of the usual two distinct SOLUTIONS, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

4a2−16a+16=16a+52

4a2−32a−36=0

a2−8a−9=0

(a−9)(a+1)=0

So the values of a are −1 and 9.

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