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Co 8. Factorise each of the following:(i) 8a + b3 +12a+b +6ab2(ii) 27-125a - 135a + 225a2 |
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Answer» (i)8a + b3 +12a+b +6ab2=(2A-b)(4a²+2ab+b²)-6ab(2a-b)=(2a-b)(4a²+2ab+b²-6ab)=(2a-b)(4a²-4ab+b²)=(2a-b){(2a)²-2×2a×b+(b)²}=(2a-b)(2a-b)²=(2a-b)(2a-b)(2a-b)ii) 27 – 125a³ – 135a + 225a²SOL: 27 – 125a³– 135a + 225a²= (3)³ – (5A)³ – 135a + 225a²= (3)³ – (5a)³ – 45a(3 – 5a)= (3)³ – (5a)³ – 3(3)(5a)(3 – 5a)Again Using (x – y)³ = x³ – y³ – 3xy (x – y)Putting nd we GET x = 3, y = 5a= (3 – 5a)³= (3 – 5a) (3 – 5a) (3 – 5a) |
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