`COCl_(2)` gas decomposes as: `COCl_(2)(g) hArr CO(g)+Cl_(2)(g)` If one mole of He gas is added in the vessel at equilibrium at constant pressure thenA. `[COCl_(2)]` increases.B. "moles" of `CO` will increases.C. The reaction goes in forward goes in forward direction.D. `K_(c )=1`

`COCl_(2)` gas decomposes as: `COCl_(2)(g) hArr CO(g)+Cl_(2)(g)` If on

1.	`COCl_(2)` gas decomposes as: `COCl_(2)(g) hArr CO(g)+Cl_(2)(g)` If one mole of He gas is added in the vessel at equilibrium at constant pressure thenA. `[COCl_(2)]` increases.B. "moles" of `CO` will increases.C. The reaction goes in forward goes in forward direction.D. `K_(c )=1`
Answer» Correct Answer - B::C `COCl_(2)(g) hArr CO(g)+Cl_(2)(g), Deltan_(g)=2-1=1` When an inert gas is added at constant `P`, the reaction shifts where `Deltan_(g) gt 0` (forward direction). Hence, (b), (c ) are correct.

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`COCl_(2)` gas decomposes as: `COCl_(2)(g) hArr CO(g)+Cl_(2)(g)` If one mole of He gas is added in the vessel at equilibrium at constant pressure thenA. `[COCl_(2)]` increases.B. "moles" of `CO` will increases.C. The reaction goes in forward goes in forward direction.D. `K_(c )=1`

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