[CoCl_(2)(NH_(3))_(4)]^(+) +Cl^(-) to [CoCl_(3)(NH_(3))_(3)] + NH_(3) – InterviewSolution

1.	[CoCl_(2)(NH_(3))_(4)]^(+) +Cl^(-) to [CoCl_(3)(NH_(3))_(3)] + NH_(3) If in the above reaction only one isomer of the product is obtained, which is true for the initial (reactant) complex :
Answer» compound is in CIS FORM compound is in TRANS form compound is in both (cis and trans) forms can't be predicted Solution : to only one possible because all 'B' position are IDENTICAL.

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