[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3). If – InterviewSolution

1.	[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3). If in this reaction two isomers of the produt are obtained, which is true for the iniital (reactant) complex:
Answer» COMPOUND is in CIS-form compound is in TRANS-form compound is in both (cis and trans) can't be predicted Solution :

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