CoCl_(3).5NH_(3).H_(2)Ois a pink solid,the solution of this salt is also pink and forms 3 mol of AgCl with silver nitrate solution. On heatingpink solid, it loses one water molecule and forms purple solid having the same ratio of Co: NH_(3) :Clas that of pink solid. The purple solid when dissolved in water and treated with silver nitrate forms 2 mol of AgCl. Draw the structures and name the pink and purple solids.

CoCl_(3).5NH_(3).H_(2)Ois a pink solid,the solution of this salt is al

1.	CoCl_(3).5NH_(3).H_(2)Ois a pink solid,the solution of this salt is also pink and forms 3 mol of AgCl with silver nitrate solution. On heatingpink solid, it loses one water molecule and forms purple solid having the same ratio of Co: NH_(3) :Clas that of pink solid. The purple solid when dissolved in water and treated with silver nitrate forms 2 mol of AgCl. Draw the structures and name the pink and purple solids.
Answer» Solution :(1) Since the COMPLEX of FORMULA `CoCl_(3).5NH_(3).H_(2)O` in the solution FORMS 3 mol AGCL , the complex contains `3Cl^(-)` in the outer ionisation sphere and the formulaof the pink coordination compound should be , `[Co(NH_(3))_(5)(H_(2)O)]Cl_(3)`. `[Co(NH_(3))_(5)H_(2)O]Cl_(3) hArr[Co(NH_(3))_(5)H_(2)O]^(3+) +3Cl^(-)` `3AgNO_(3) + 3Cl^(-) hArr 3AgCl_((S)) + 3NO_(3)^(-)` (2) On heating, the pink solid loses one `H_(2)O` molecules and in the aqueous solution gives 2 mol `AgCl`, with same ratio of `Co:NH_(3)`, the purple coordination compound should be, `[Co(NH_(3))_(5)Cl]Cl_(2)` having the same ratio of `Co:NH_(3)(1:5)` `[Co(NH_(3))_(5)Cl]Cl_(2) hArr [Co(NH_(3))_(5)Cl]^(2+)+2Cl^(-)` `2AgNO_(3) + 2Cl^(-) hArr 2AgCl_((S)) + 2NO_(3)^(-)`. IUPAC names of complexes : Pink complex `[Co(NH_(3))_(5)H_(2)O]Cl_(3)` : Aquapentaamminecobalt (III) Chloride. Purple complex `[Co(NH_(3))_(5)Cl]Cl_(2)` : Pentaamminechloridocobalt(III) chloride.