1.

Coefficent of variation of two distributions are 60% and 75%, and their standard deviations are 18 and 15 respectively. Find their arithmetic means.

Answer» Given : `CV_(1)=60, CV_(2)=75, sigma_(1)=18 and sigma_(2)=15.`
Let `barx_(1) and barx_(2)` be the means of 1st and 2nd distribution respectively.
Then,
`CV_(1)=(sigma_(1))/(x_(1))xx100rArrbarx_(1)=(sigma_(1)xx100)/(CV_(1))`
`rArr" "barx_(1)=(18xx100)/(60)=30.`
`CV_(2)=(sigma_(2))/(x_(2))xx100rArrbarx_(2)=(sigma_(2)xx100)/(CV_(2))`
`rArrbarx_(2)=(15xx100)/(75)=20.`
Hence, `barx_(1)=30 and barx_(2)=20.`


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