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Coefficient of thermal expansion of a wire varies with temperature T asalpha = 1.6 xx 10^(-6) T, where T is temperature in degree Celsius. If the length of wire is 10 m at 0^@C, what is the change in length of wire (in mm), when its temperature is raised to 25^@C? |
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Answer» `int_0^(Delta L) dl = l_0 alpha_0 int_0^25 TdT` `Delta l = l_0 alpha_0 xx 625/2 "" = 10 xx 1.6 xx 10^(-6) xx 625/2 = 5 xx 1000 xx 10^(-6) = 5 mm`. |
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