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Coefficients of variation of two distributions are 50 and 60, and their arithmetic means are 30 and 25, respectively. Difference of their standard deviations is |
Answer» Correct Answer - A Here, `(CV)_(1)=50,(CV)_(2)=60,overline(x_(1))=30 " and" overline(x_(2))=25` ` therefore (CV)_(1)=(sigma_(1))/(overline(x_(1)))xx100` `implies 50=(sigma_(1))/(30)xx100` `therefore sigma_(1)=(30xx50)/(100)=15` and `CV_(2)=(sigma_(2))/(overline(x_(2)))xx100` `implies 60=(sigma_(2))/(25)xx100` `therefore sigma_(2)=(60xx25)/(100)=15` Now, `sigma_(1)-sigma_(2)=15-15=0` |
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