Saved Bookmarks
| 1. |
Columb law for electrostatic force between two pointcharges and newtonlaw for gravitational force between twothe distancebetween the chargesand masses respectively (a) compare the strength of these forces by determining the ratioof their magnitudes (i) for an electronand a proton and (ii) for two protons(b) estimate the acceleratons of electron and proton due to theelectrical force oftheir mutual attarction when they are 1A (=10^(-10) m) a part (m_(p)=1.67xx10^(27) kg m_(e )=9.11xx10^(-31) kg) |
|
Answer» Solution :(a) (i) The electricforce betweenan electron and a protonat a distancer apart is where the negativesign indicates that the force isattarctive the correspondinggravitationforce `F_(G)=-G(m_(p)m_(e))/(r_(3))` however it may be mentionedhere that the sign of the two forcesare differentof these FORCES between two protonsinside a nucleus are `f_(e )-230 N`the ratio of the two forces showsthat electricalforces are enormously stonger than thethe gravitationalforces using newton secondlaw of motionf=ma the acceleration that an electron will undergo is comparing this with the value of acceleration due to gravitywecan conclude that the EFFECT of gravitationall field is NEGLIGIBLE on the motion of electronunder the actionof coulomb force due ot a proton the valuefroacceleartionof the proton is `2.3xx10^(8)N//1.67 xx10^(27) kg =1.4 xx10^(19) m//s^(2)` |
|