{:(,"Column A",,"Column B"),("(A)","Liquid displaced by solid" ,"(a)",10^(5)g),("(B)","1 quintal","(b)",10^(9)mg),("(c)","1 tonne","(c)","Unit of pressure"),("(D)", "kgwt "m^(-2) ,"(d)"," Volume of the solid"):}

{:(,"Column A",,"Column B"),("(A)","Liquid displaced by solid" ,"(a)",

1.	{:(,"Column A",,"Column B"),("(A)","Liquid displaced by solid" ,"(a)",10^(5)g),("(B)","1 quintal","(b)",10^(9)mg),("(c)","1 tonne","(c)","Unit of pressure"),("(D)", "kgwt "m^(-2) ,"(d)"," Volume of the solid"):}
Answer» `A to a, B to b, C to c, D to d` `A to d, B to c, C to b, D to a` `A to d, B to a, C to b, D to c` `A to d, B to b, C to c, D to a` Solution :A -d "" When a body with density more than the density ofliquid is immwesed, the volume of the displaced liquid is EQUAL to the volume of the solid. B- a ""One quintal = 100 kg But one kg = 1000 g `:.` One quintal = `100 xx 1000` " g " One quintal = `10^(5)` " g 'C-b ""One tonne = 1000 kg But one kg = 1000 " g " And one g = 1000 mg `:.` One tonne = `1000xx 1000xx 1000`" mg " One tonne = `10^(9)` " mg " D-c ""kgwt `m(-2)` = kgwt // ` m^(2)` kgwt is unit of force and `m^(2)` is unit of AREA. Force per unit area is called pressure. `:.` kgwt `m^(-2)` is unit of pressure.