Saved Bookmarks
| 1. |
{:("Column-I","Column-II"),("(Analysis of Atoms)","(Characteristics)"),((A)"Total number of orbitals with m=0 in "._30 "Zn atom","(p)Number is even"),((B)"Total number of electrons with l=0 in "._12 "Mg atom","(q)Number is odd"),((C )"Maximum number of electrons with l+m=0 in"._17 "Cl atom","(r)Number is same as the number of unpaired electrons in "._25Mn^(2+)"ion"),((D)"Total number of electrons with anticlockwise spin in "._10 "Ne atom","(s)Number is greater than 5 "),(,"(t)Number is less than the number of fully filled orbitals in "._18Ar"atom"):} |
|
Answer» Total number of orbitals with m=0 i.e. 1+1+1+1+1+1+1=7 `._12Mg=1s^2 , 2s^2 , 2p^6 , 3s^2` s-orbitals have l=0 So, number of ELECTRONS =2+2+2=6 `._17Cl^(35)=1s^2 , 2s^2, 2p^6, 3s^2 3p^6` max. noof ELECTRON with l+m=0 will be : for s-orbitals , no of electrons =2+2+2=6 for p-orbitals , max no of electrons =2+2=4 So, max of total electrons=6+4=10 `._10Ne^20 =1s^2 , 2s^2 , 2p^6` 5 electrons will have anticlockwise spin. Number of unpaired electron in`._25Mn^(2+)` ion=`1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5=5` Number of fully filled orbitals in `._18Ar` ATOM =`1s^2, 2s^2 , 2p^6, 3s^2 , 3p^6 =1+1+3+1+3=9` |
|