1.

{:("COLUMN - I" , "COLUMN - II"),("(oxo - acod)","(ox.state of P)"),("A)"H_3PO_3,"p)"+4),("B)" H_3PO_2,"q)" +1),("C)" H_4P_2O_6,"r)" +3),("D)" H_4P_2O_7,"s)" +5):}

Answer»


Solution :A) `H_3PO_3-3(+1)+x+3(-2)=0,+3,+x-6=0, x =+6 -3=+3,p=+3`
B) `H_3PO_2-3(+1)+x+2(-2)=0, +3+x -4=0 , x =+4-3=+1,p=+1`
C) `H_(4)P_(2)O_6-4(+1)+2X+6(-2)=0, +4+2x-12=0 , 2x +12 -4 =+8,x =+8//12 =+4P=+4`
D) `H_4P_2O_7-4(+1)+2x+7(-2)=0,+4+2x-14=0,2x=+14-4=+10,x =+10//2 =+5,P=+5`


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