Combination between Pt(IV), NH_3 and Cl^(-) results in the formation of seven complexes. One of these complexes is [Pt(NH_3)_6]Cl_4 (i) Writethe formulae and IUPAC names of the other six complexes . (ii)Which will have highest molar conductivity ? (iii) Which of these is non-ionic ? (iv)What is thethe C.N of Pt in these complexes ?

Combination between Pt(IV), NH_3 and Cl^(-) results in the formation o

1.	Combination between Pt(IV), NH_3 and Cl^(-) results in the formation of seven complexes. One of these complexes is [Pt(NH_3)_6]Cl_4 (i) Writethe formulae and IUPAC names of the other six complexes . (ii)Which will have highest molar conductivity ? (iii) Which of these is non-ionic ? (iv)What is thethe C.N of Pt in these complexes ?
Answer» Solution :(i) The structures and IUPAC names of other SIX complexes are : (a) `[Pt(NH_3)_(5)CL]Cl_3` : pentaammine chloridoplatinum (IV) chloride . (b) `[Pt(NH_3)_(4)Cl_2]Cl_2` : tetraamminechloridoplatinum (IV) chloride . (c) `[Pt(NH_3)_(5)Cl_3]Cl` : triamminetrichloridoplatinum (IV) chloride (d) `[Pt(NH_3)CL_4]` : diamminetetrachloridoplatinum (IV) (e) `[Pt(NH_3)Cl_5]^(-)` : amminepentachloridoplatinate(IV) (f) `[PtCl_6]^(2-)` : hexachloridoplatinare (IV) (ii) The complex `[Pt(NH_3)_6]Cl_4` has the maximum MOLAR conductivity asit forms maximum ion (five) in SOLUTIION. (iii) The compound (d) is non-ionic. (iv) The C.N of Pt in all the complexes is 6.