1.

Combustion of glucose takes place according to the equation, C_(6)H_(12)O_(6)+6O_(2)rarr6CO_(2)+6H_(2)O, DeltaH=-72 kcal.How much energy will be required for the production of 1.6 g of glucose (Molecular mass of glucose = 180 g)

Answer»

0.064 KCAL
0.64 kcal
6.4 kcal
64 kcal

Solution :`DELTAH` PER 1.6 g = `(72xx1.6)/(180)=0.64` KJ


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