1.

Commercially available cone. HCI contains 38% HCI by mass density of 1.19 g cm^(3). Calculate the molarity of this solution.

Answer»


Solution :Mass of HCI in solution = 38 G , Mass os SOUTION = 100 g
DENSITY of solution `=1.19" g mol"^(-3)`
`"Volume of 100 g of solution"=((100g))/((1.19cm^(-3))=84 cm^(3)`.
`"Molarity of solution (M)"=("Mass of HCI/Molar mass")/("Volume of solution in dm"^(-3))=((38.0g)//(36.5" g mol"^(-1)))/(84//1000(DM^(3)))=12.39 m`.


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