Commet on the reactions of dihydrogen with (a) chlorine,(b) sodium and

1.	Commet on the reactions of dihydrogen with (a) chlorine,(b) sodium and (c) copper (II) oxide.
Answer» dihydrogen reduces chlorine into chloride `(Cl^(ɵ))` ion and itself gets oxidised to `H^(o+)` ion by chlorine to form hydrogen chloride. An electron pair is shared between `H` and `Cl` leaving to the formation of a covalent molecule. `H_(2g)+Cl_(2g)tounderset("Hydrogen chloride")(2HCl_(g))` (b) Dihydrogen is reduced by sodium to form `NaH`. an electron is transfer from `Na` to `H` leading to the formation of an ionic compound, `Na^(o+)H^(ɵ)`. red between `H` and `Cl` leaving to the formation of a covalent molecule. `H_(2g)+2Na_(2g)tounderset("Sodium hydride")(2NaH_(s)` (c) Dihydration reduces copper `(II)` oxide to copper in zero oxidation state and itself gets oxidised to `H_(2)O`, which is a covalent molecule. `H_(2(g))+CuOtoCu_(s)+H_(2)O_((1))`

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