1.

Common salt obtained from sea-water contains 95% NaCl by mass. The approximate number of molecules present in 10g salt is:

Answer»

`10^(21)`
`10^(22)`
`10^(23)`
`10^(24)`

Solution :Mass of NaCl in 10G salt`=10xx(95)/(100)=9.5g`
NUMBER of MOLECULES of `NaCl=(9.5)/(58.5)xx6.023xx10^(23)`
`=9.78xx10^(22)=10^(23)`


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