1.

Common salt obtained from sea water contains95% NaCl by mass. The approximate number of molecules present in 10g of the salt is

Answer»

`10^21`
`10^22`
`10^23`
`10^24`

SOLUTION :NUMBER of molecules in 10 g of NaClhaving 95% purity
` = (6.023 XX 10^23)/(58.5) xx 10 xx 95/100`
`= 9.78 xx 10^22 = 10^23`


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