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| 1. |
Compare I_("max") and I_("min") with amplitudes of the interfering waves. |
| Answer» SOLUTION :`(I_("max"))/(I_("min"))=((r+1)/(r-1))^2` where `=(A_1)/(A_2). A_1 & A_2` are the amplitudes of the INDIVIDUAL interfering WAVES. | |