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Compare the reduction potentials of Mn^(3+) // Mn^(2+) and Fe^(3+) // Fe^(2+). |
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Answer» SOLUTION :`Mn^(3+)+ e^(-) to Mn^(2+)E^(0)= +1.51V` `Fe^(3+)+ e^(-)E^(0)= +0.77V` (ii) The high reduction potential of `Mn^(3+) // Mn^(2+)` INDICATES `Mn^(2+)` is more stable than `Mn^(3+)` For `Fe^(3+) // Fe^(2+)`the reduction potential is 0.77V, this low VALUE indicates that both `Fe^(3+)` and `Fe^(2+)`can exist under normal conditions, (iii) The drop from Mn to Fe is due to the electronic structure of the ions concerned. `Mn^(3+)` has `3d^(5)` CONFIGURATION while that of `Mn^(2+)` is `3d^(5)`. The extra stability associated with a half filled d sub-shell MAKES the reduction of `Mn^(3+)` very feasible. |
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