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Complete the equation : [Fe(H_(2)O)_(6)]^(2+) + NO rarr |
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Answer» Solution :NO reduces `FE^(2+)` to `Fe^(+)` and itself gets oxidised to nitrosonium ion `(NO^(+))`. The two SPECIES then combine to form a brown complex. `[Fe(H_(2)O)_(6)]^(2+)(aq) + NO(g) RARR underset(("Brown complex"))underset("Pentaaquanitrosonium IRON (I)")([Fe^(+)(H_(2)O)_(5)NO^(+)](aq)) + H_(2)O(l)` |
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