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Complete the following reaction equation : NaClO_(3) (aq) + SO_(2)(g) rarr |
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Answer» SOLUTION :`CIO_(3)^(-)` being an oxidising agent oxidises `SO_(2)` to `SO_(4)^(2-)` and itself gets REDUCED to `ClO_(2)`. Alternatively, `SO_(2)` being a reducing agent reduces `ClO_(3)^(-)` to `ClO_(2)` and itself oxidised to `SO_(4)^(2-)` `underset("Sod. CHLORATE")(2 NaClO_(3)(aq))+SO_(2)(g) RARR underset("Chlorine dioxide")(2 ClO_(2)(g)) + Na_(2)SO_(4)(aq)` |
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