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Complete the following : XeF_(2) + PF_(5) rarr |
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Answer» SOLUTION :Due to the presence of three lone pairs of electrons, `XeF_(2)` acts as a fluoride ion donor while due to the presence of vacant `sp^(3)d` orbitals, `PF_(5)` acts as a fluoride ion acceptor. In other WORDS, `XeF_(2)` acts as a Lewis base while `PF_(5)` acts as a Lewis acid to form the corresponding adduct. `underset("Lewis base")(XeF_(2)) + underset("Lewis acid")(PF_(5)) rarr underset("Adduct")([XeF]^(+)[PF_(6)]^(-))` |
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