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Composition of a sample of Wustite is Fe_(0-93)O_(1-0). What percentage of iron is present in the form of Fe (III)? |
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Answer» Solution :`Fe_(0.93) O_(1-0)` is non-stoichiometric is a mixture of `Fe^(2+)` and `Fe^(3+)` ions. LET atoms of`Fe^(3+)`ions are present in the compound. This means that x`Fe^(3+)` ions have been replaced by`Fe^(2+)` ions. No. of `Fe^(2+)` ions = 0.93 - x For electrical neutrality, Positive charge on the compound = NEGATIVE charge on the compound 2 (0.93 - x) + 3x = 2 1.86 + x = 2 x = 0.14 age of `Fe^(3+)` ions = `(0.14)/(0.93) XX 100` = 15.05 |
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