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Composition of sample wurtzite is Fe_(0.93)O_(1.0). What percentage of iron is present in the form of Fe(III) ?

Answer»


Solution : `Fe_(0.93)O_(1.0)` is a non-stoichiometric compound and contains MIXTURE of `Fe^(2+)` and `Fe^(3+)` ions. Let x `Fe^(3+)` ions are present in the compound. This MEANS that `xFe^(2+)` ions have been replaced by `Fe^(3+)` ions.
No. of `Fe^(2+)` ions in the compound = 0.93 – x
For electrical neutrality, total positive charge on cations = Total NEGATIVE charge on anions.
`:.` 2 (0.93 - x) + 3X = 2 or 1.86 +x=2 or x=0.14
`:.` Percentage of `Fe^(3+)` ions = (0.14)/(0.93)XX 100 = 15.05%`


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