Compound A(C_(6)H_(13)NO) liberates hydrogen on reaction with metallic sodium. A on reaction with NaNO_(2) and HCl was found to give three products B(C_(6)H_(10)O),C(C_(6)H_(10)O) and D(C_(6)H_(12)O_(2)) a vicinal. Both B & C react with 2,4 – DNP to give coloured product. C reduces Fehling's solution, but not B. B on reduction with HI & Red P gave cyclohexane while C gave methylcyclophentane. Don reduction with HI & Red P also gave cyclohexane. Study the reaction give above carefully and answer the following questions. The structure of Compound 'A' is

Compound A(C_(6)H_(13)NO) liberates hydrogen on reaction with metallic

1.	Compound A(C_(6)H_(13)NO) liberates hydrogen on reaction with metallic sodium. A on reaction with NaNO_(2) and HCl was found to give three products B(C_(6)H_(10)O),C(C_(6)H_(10)O) and D(C_(6)H_(12)O_(2)) a vicinal. Both B & C react with 2,4 – DNP to give coloured product. C reduces Fehling's solution, but not B. B on reduction with HI & Red P gave cyclohexane while C gave methylcyclophentane. Don reduction with HI & Red P also gave cyclohexane. Study the reaction give above carefully and answer the following questions. The structure of Compound 'A' is
Answer» Solution : COMPOUND C having aldehydic group so FEHLING solution REDUCES