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Compound (A) has a neutralization equivalent of 116. It forms a semicarbazone or phenyl hydrazone, and gives positive iodoform test. Compound (A) gives n-pentane. What are (A), (B) and (C)? |
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Answer» Solution :(i) Since (A) forms semicarbazone and phenyl hydrazone, hence it has a gt C=O group. As it ALSO gives iodoform test hence it contains `H_(3)C-overset(O)overset(||)(C)-` group in its molecule. (ii) The NEUTRALIZATION equivalent of (A) is 116, it is also contain a -COOH group. its formula can be deduced as followes `116-H_(3)C-overset(O)overset(||)(C)-+-COOH=116-(43+45)=28` The value 28 corresponding to two methyl groups. 
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