1.

Compound 'A' of molecula formula C_(4)H_(10)O on treatment with Lucas reagent at room temperature gives compound 'B'. When compound 'B' is heated with alcoholic KOH, it gives isobutene. Compound 'A' annd 'B' are respectively

Answer»

2-methyl-2-propanol ad 2-chloro-2-methyl-propane
2-methyl-1-propanol and 1-chloro-2-methyl-propane
2-methyl-1-propanol and 2-chloro-2-methyl-propane
butan-2-ol and 2-chlorobutane

Solution :Since compound (A) with M.F. `C_(4)H_(10)O` on treatment with Lucas reagent room temperature gives compound (B), therefore, (A) must be `3^(@)` alcohol, i.e., 2-methyl-2-propanol and (B) must be 2-chloro-2-methylpropane, i.e., option (a) is correct
`underset("2-Methyl-2-propanol (A) M.F. "C_(4)H_(10)O" "(3^(@)" alcohol"))(CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-OH) underset(+"anhyd. "ZnCl_(2)" (Lucas reagent)")overset("conc. HCl")to underset("2-Chloro-2-methyl-propane (B)")(CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CL)`


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