1.

Compound I and II can be distinguished by using reagent. underset("4-Hydroxy-4-methylpent-2-enoic acid")((I))"" underset("5-Hydroxypent-2-ynoic acid")((II))

Answer»

`NaHCO_(3)`
`Br_(2)//H_(2)O`
`HCl//ZnCl_(2)` (anhydrous)
`Cu_(2)Cl_(2)//NH_(4)OH`

Solution :`underset((I))(underset(HOOC)underset(|)(HC)=underset(H)underset(|)(C )-underset(OH)underset(|)OVERSET(CH_(3))overset(|)(C )-CH_(3))` " " `underset((II))(underset(HOOC)underset(|)(C )-=C-CH_(2)-underset(OH)underset(|)(CH_(2)))`
`(I)` gives IMMEDIATE turbidity by Lucas REAGENT and `(II)` does not give turbidity appriciably.


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