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Answer» `K_(2)Cr_(2)O_(7)` `(NH_(4))_(2) [TiCl_(6)]` `VOSO_(4)` `K_(3)[CU(CN)_(4)]` Solution :`K_(2)Cr_(2)O_(7)` contains `Cr^(6+) (3d_(@)) ion` which is diamagnetic and is coloured due to charge transfer, and `(NH_(4))_(2) [TiCI_(6))]` contains `Ti^(4+) (3d^(@))` which is diamagnetic and colourless, `VOSO_(4)`, contains `V^(4+)(3d^(1))` which is paramagnetic and coloured `K_(3)[Cu(CN)_(4)]` contains `Cu^(+) (3d^(10))` which is diamagnetic and colourless. Hence, (C) is the correct ANSWER.
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