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Compounds with spinonly magnetic moment equivalent to five unpaired electrons are |
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Answer» `K_(4)[Mn(CN)_(6)]` `CN^(-)` is a strong field ligand, so pairing will TAKE place i.e. `t_(2g)^(2,2,1) e_(g)^(0,0)` B. `[Fe(H_(2)O)_(6)]Cl_(3),Fe^(3+)=[Ar]3d^(5)4s^(0)` `H_(2)O` is a weak field ligand so pairing will not occur. i.e. `t_(2g)^(1,1,1), e_(g)^(1,1)` c. `K_(3)[FeF_(6)],Fe^(3+)=[Ar]3d^(5) 4s^(0)` `F^(-)` is a weak field ligand, so, pairing will not occur. i.e `t_(2g)^(1,1,1) e_(g)^(1,1)` d. `K_(4)[MnF_(6)], Mn^(2+)=[Ar]3d^(5)4s^(0)` `F^(-)` is a weak field ligand so, pairing will not occur. i.e. `t_(2g)^(1,1,1)e_(g)^(1,1)` HENCE b, c and d complexes will SHOW spin only magnetic moment equivalent to five unpaired electrons. |
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