InterviewSolution
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InterviewSolution
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Compute the bulk modulus of water from the following data : initial volume = 100.0 litre, pressure increase = 100.0 atmosphere. Final volume - 100.5 litre . (1 atmosphere = `1.013 xx 10^(5) Pa)`. Compare the ulk modulus of water that of air (at constant temperature). explain in simple terms why the ratio is so large. |
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Answer» Here, `V = 100 litre = 100 xx 10^(-3) m^(3) , p = 100 atm. = 100 xx 1.013 xx 10^(5) Pa`. `V =Delta V = 100.5litre or Delta V = (V + Delta V) -V = 100.5-100 = 0.5 litre = 0.5 xx 10^(-3)m^(3)` We know that bulk moduls, `B = (pV)/(Delta V) = (100 xx 1.013 xx 10^(5) xx 100 xx 10^(-3))/(0.5 xx 10^(-3)) = 2.026 xx 10^(9) Pa`. Bulk modulus of air at constant temperature = atmospheric pressure = `1.013 xx 10^(9) Pa` `("Bulk modulus of water")/("Bulk modulus of air") = (2.026 xx 10^(9))/(1.013 xx 10^(5)) = 2.0 xx 10^(4)` It is so because gases are much more compressibel than those of liquids. the molecules in gases are very poorly coupled to their neighbours as compared to those of gases. |
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