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Compute the following sums : \(\begin{bmatrix} 3& -2 \\[0.3em] 1 &4 \\[0.3em] \end{bmatrix}\)\(+\begin{bmatrix} -2&4 \\[0.3em]1 & 3 \\[0.3em] \end{bmatrix} \) |
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Answer» \(=\begin{bmatrix} 3-2& -2+4 \\[0.3em] 1+1 &4+3 \\[0.3em] \end{bmatrix}\) \(=\begin{bmatrix} 1& 2 \\[0.3em] 2 &7 \\[0.3em] \end{bmatrix}\) Hence, \(\begin{bmatrix} 3& -2 \\[0.3em] 1 &4 \\[0.3em] \end{bmatrix}\)\(+\begin{bmatrix} -2&4 \\[0.3em]1 & 3 \\[0.3em] \end{bmatrix} \) = \(\begin{bmatrix} 1& 2 \\[0.3em] 2 &7 \\[0.3em] \end{bmatrix}\) |
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