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Compute the magnetic of the magnetic field of a long, straight wire carrying a current of 1 A at distance of 1m from it. Compare it with Earth's magnetic field . |
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Answer» Solution :Given that I = l A and radius r = l m `B_("straightwire") = (mu_(0)l)/(2pi r) = (4 PI XX 10^(-7) xx l)/(2 pi xx l ) = 2 xx 10^(-7) `T but the EARTH.s magnetic field is `B_("Earth") ~ 10^(-5)` T So, `B_("straightwire")` is one hundred times smaller than `B_("earth")`. |
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