1.

Compute the mode for the following frequency distribution :

Answer» Clearly the modal class is 20-30 as it has the maximum frequency.
`:. l= 20, f_(1) = 28, f_(0) = 16, f_(2) = 20`
and ` h = 10`
Mode `M = l + (f_(1)-f_(0))/(2f_(1)-f_(0)-f_(2)) xx h`
Mode `M = 20 + (28-16)/(2 xx 28 - 16 - 20) xx 10`
`= 20 + (12)/(56-16-20) xx 10 = 20+(12)/(20) xx 10 = 26`.
Hence, mode = 26


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