1.

Conant Finkelstein reaction for the preparation of alkyl iodide is based upon the fact that

Answer»

SODIUM IODIDE is soluble in METHANOL, while sodium chloride is insoluble in methanol
Sodium iodide is soluble in methanol, while NaCl and NaBr are insoluble in methanol
Sodium iodide is insoluble in methanol, whileNaCl and NaBr are solubl
The three halogens differ CONSIDERABLY in their electronegativity

Solution :`R-X+underset("soluble in" (CH_(3)OH, Me_(2)CO))(NaI) overset("acetone")(to)R-I+underset("Insoluble in " (CH_(2)OH, Me_(2)CO))(NaXdarr)`


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