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Concentrated aqueous sulphuric acid is 98% H_(2)SO_(4) by mass and has a density of "1.80 g mL"^(-1). Volume of the acid required to make one litre of 0.1 M H_(2)SO_(4) solution is |
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Answer» 5.55 mL i.e., 100/1.80 mL = 55.5 mL Also `"98 g "H_(2)SO_(4)="1 mole "H_(2)SO_(4)` `therefore"Molarity of 98% "H_(2)SO_(4)` solution `=(1)/(55.5)xx"1000 mol L"^(-1)` Now, `M_(1)V_(1)=M_(2)V_(2).` HENCE, `(1000)/(55.5)MxxV_(1)="1000 mL"xx0.1M` `"or"V_(1)=5.55mL` |
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