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Concentrated nitric acid used in the laboratory work is 68% nitric acid by mass in aquequs solution. What should be molarity of such sample of the acid if the density of solution is 1.504 g mL""^(-1) ? |
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Answer» Solution : 68%` HNO_3` means that 68 g `HNO_3 ` is PRESENT in 100 g of solution. Moles of `HNO_3 = (68)/(63 ) = 1.08 ` Density of solution = 1.504 g mL`""^( -1)` VOLUME of solution `=(1000 )/( 1.504 )=66.49` Molarity `= (1.08)/(66.49)xx1000` |
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