1.

Concentration of Cl^(-) ions in a solution obtained by mixing 600 ml of 0.1 M CaXl_(2) and 400 ml of 0.4 M AlCl_(3).

Answer»

`0.28 M`
`0.6 M`
`0.22 M`
`0.54 M`

SOLUTION :`{:(CaCl_(2),rarr,Ca^(+2),+,2Cl^(-),),(0.1 xx (600)/(1000),,,,0.12 "mole",),(AlCl_(3),,rarr,AL^(+3) + 3 Cl^(-),,),(0.4 xx (400)/(1000) " mole",,,,0.48 " mole",):}`
`n_(Cl^(-)) = (0.12 + 0.48) " mole" = 0.6 " mole"`
`V_(T) = V_(1) + V_(2) = (400 + 600) mL`
= 1 litre
`M_(Cl) = (0.6)/(1) = 0.6 M`


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