1.

Condider two rods of same length and different specific heats (s_(1), s_(2)), thermal conductivities (K_(1), K_(2)) and areas of cross-section (A_(1), A_(2)) and both having temperatures (T_(1), T_(2)) at their ends. If their rate of loss of heat due to conduction are equal, then

Answer»

`K_(1)A_(1) = K_(2)A_(2)`
`(K_(1)A_(1))/(s_(1)) = (K_(2)A_(2))/(s_(2))`
`K_(2)A_(1) = K_(1)A_(2)`
`(K_(2)A_(1))/(s_(2)) = (K_(1)A_(2))/(s_(1))`

ANSWER :a


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