1.

Conducitivity kappa, is equal to____

Answer»

`(1)/(R)(l)/(A)`
`(G^(**))/(R)`
`wedge_(m)`
`(l)/(A)`

Solution :`R=rho.(1)/(A)` or `R=(1)/(KAPPA)(1)/(A)` or `kappa`(conductivity)`=(1)/(R)(1)/(A)`, i.e., (a)
As `(1)/(A)=G^(@)` (cell constant), `kappa(1)/(R)G^(@)=(G^(**))/(R)` , i.e., (B)`.


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