1.

Conductanceof 0.1 MKCl (condiuctivity = X ohm^(-1)cm^(-1)) filled in a condictivity cell is Y ohm^(-1). If the conductance of 0.1 Mno OH filled in the csamecell is Z ohm^(-1), them olar conductance of NaOH will be

Answer»

`10^(3) (XZ)/(Y)`
`10^(4)(XZ)/(Y)`
`10(XZ)/(Y)`
`0.1 (XZ)/(Y)`

Solution :Conductivity (X) = conductance (C ) `XX` CELL constnat
`therefore` Cell CONSTANT `=X/Y`
Conductivity of `NAOH = X/Y.Z`
`Delta M (NaOH) = X/Y . Z xx (1000)/(0.1) =(XZ)/(Y) 10^(4)`


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