conductivity cell hastwoelectrodes 20mm apart and ofcrosssectionarea 1 – InterviewSolution

1.	conductivity cell hastwoelectrodes 20mm apart and ofcrosssectionarea 1.8 cm^(2). Find thecellconstant.
Answer» SOLUTION :Distancebetweentwo ELECTRODES = L= 20 mm= 2 cm Crosssectionarea = a= 1.8 `cm^(2)` Cellconstant = b = ? `b= (1)/(a) =(2)/(1.8)= 1.111 cm^(-1)`

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