1.

Conductivity kappa, equal to _____

Answer»

`(1)/(R)(L)/(A)`
`(G^(**))/(R)`
`Lamda_(m)`
`(l)/(A)`

Solution :* Resistance of any SUBSTANCE is directly proportional to its length and inversely proportional to its cross-sectional area.
`R ALPHA(l)/(A)` So, `R=rho(l)/(A)=(l)/(kappaA)`
* Where, `rho` is resistance or specific resistance.
`therefore rho=(RA)/(l)""therefore (1)/(R)=(1)/(rho)XX(A)/(l)`
`(1)/(rho)=kappa""therefore (1)/(R)=kappa((A)/(l))`
`therefore kappa=(1)/(R)=kappa((A)/(l))`. . . (A)
`(l)/(A)=G^(**)""therefore kappa=(G^(**))/(R)` . . . (B)
Where `G^(**)=(l)/(A)`=cell constant, `kappa`=conductivity of solution.


Discussion

No Comment Found

Related InterviewSolutions